**SEMI‐ROUND STAIR‐CASE CALCULATION | QUANTITY SURVEY |
VOLUME OF CONCRETE & AREA OF SHUTTERING**

**For a given drawing of a Semi‐round Stair‐case find**

1. Volume of Concrete

2. Area of Shuttering

**Height
of riser = 0.15m**

**Tread
= 0.10m**

**Radius
of waist Slab = 3.50m**

** **

**Height
of Ceiling** = Height of Riser x No. of Riser

= 0.15 x 24

**= 3.60m**

** **

**Waist
Slab thickness = 0.15m **

**Width
of Waist Slab = 1.30m **

**no.
of Step = 24**

**(A) Solution for staircase:**

To find out **Semi‐Circle
Length** the formula = 2 x π x r x 0.50 **Therefore,**

Radius of waist slab 'r'= 3.50m

= 2 x π x 3.5 x 0.50

**=
10.99m (linear length)**

Inclined length = √(10.99^{2}
+ 3.60^{2})

**C =
11.56m**

**1. Waist Slab:**

**(a)
Volume of Concrete for waist slab** = Area x thickness

= L x B x D

= 11.56 x 1.30 x 0.15

**=
2.254 m ^{3}**

**(b)
Shuttering Area for waist slab** = L x D x 2 + B x D + L x
B

= 11.56 x 0.15 x 2 + 1.30 x 0.15 + 11.56 x 1.30

**=
18.691 m ^{2}**

**2. Steps:**

Length of step = 1.30m

Width of tread = 0.30m on one side and 0.40m on other
side Average width of riser = (0.30 + 0.40)/2

B = 0.35m

Height of Riser = 0.15m

**(a)
Volume of Concrete for Step** = Area x length of step x no. of steps

= 1/2 x b x h x L x no. of steps

= 0.50 x 0.35 x 0.15 x 1.3 x 24

**=
0.819 m ^{3}**

**(b)
Shuttering area for Step** = (1/2 x B x H x 2 + L x D) x no.s

= (0.50 x 0.35 x 0.15 x 2 + 1.30 x 0.15) x 24

**=
5.94 m ^{2}**

**3. Hand‐Rail :**

**Therefore,**

L = 11.56m

B = 0.10m D = 0.80m

no.s = 2

**(a)
Volume of Concrete for Hand‐Rail** = area x depth x no. of
Hand rails

= L x B x D x no.s

= 11.56 x 0.10 x x 0.80 x 2

**=
1.849 m ^{3}**

**(b)
Shuttering area for Hand‐Rail** = (L+B) x 2 x D x no.s

= (11.56 + 0.10) x 2 x 0.80 x 2

**=
37.312 m ^{2}**

**(i)
Total Concrete for stair case** = 2.254 + 0.819 + 1.849

**=
4.922 m ^{3}**

**(ii)
Total Shuttering area for stair‐case** = 18.691 + 5.94 + 37.312

**=
61.943 m ^{2}**

^{}

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